Back to Blog
![]() ![]() To achieve an angular acceleration of 18.00 radians/s 2, what torque is required?Īnswer: The torque can be found using the torque formula, and the moment of inertia of a thin rod. Assume a helicopter blade is a thin rod, with a mass of 150.0 kg and a length of 8.00 m. This formula applies to every bit of the object that’s rotating each bit of mass has this kinetic energy. It is called the moment of inertia of the rigid body, and its SI units are kg·m2. The torque applied to one wheel is 0.0020 N∙m.Ģ) The moment of inertia of a thin rod, spinning on an axis through its center, is, where M is the mass and L is the length of the rod. where m is the mass of the object and v is the speed. J A : Moment of inertia of load kgm 2 J 1 : Moment of inertia of the motor-side gear kgm 2 J 2 : Moment of inertia of the load-side gear kgm 2 JJ 1 + (J A + J 2 ) (. Z 2 : Teeth number of the load-side gear. Z 1: Teeth number of the motor-side gear. Since we have a solid disk as our pulley, the moment of inertia is. The parallel axis thereom is used to seperate the shape into a number of simpler shapes. If the angular acceleration of a wheel is 1.00 radians/s 2, what is the torque?Īnswer: The torque can be found using the torque formula, and the moment of inertia of a solid disc. Motor Shaft Conversion Moment of Inertia. We define torque as the measure of force that can cause an object to rotate. The moment of inertia can be calculated by hand for the most common shapes: Rectangle: (bh3)/12 >Circle: (pi r4)/4 Triangle: (bh3)/12 If the shape is more complex then the moment of inertia can be calculated using the parallel axis thereom. The wheels of a toy car each have a mass of 0.100 kg, and radius 20.0 cm. ![]() 1) The moment of inertia of a solid disc is, where M is the mass of the disc, and R is the radius. ![]()
0 Comments
Read More
Leave a Reply. |